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Models
Manufacturing Example

Convex Objective: Product Revenue a Convex Function of Sales

A slight change in the assumptions alters the structure of the problem significantly and makes it much harder to solve. To see this, suppose the products have increasing rather than decreasing marginal revenues. For the example, assume the following relationships.

This is just opposite of the previous situation where now the marginal revenue of P starts at 45 and ends at 90. Similar relations hold for Q and R. Although this may seem odd for most products these functional forms serve to illustrate what happens when revenue is a convex function of the decision variables. The new objective function is

We substitute this objective in the LP to form a nonlinear programming model with a convex objective function. The linear constraints of the LP are still valid.

Solution to the Convex Model
 

The new problem was solved with the nonlinear programming code available in the Excel Solver.  The algorithm embedded in this code, as well as in all nonlinear solvers, is an iterative procedure that starts with an initial solution and searches over the decision space until a feasible solution is reached such that no improvement is possible within its neighborhood.  Informally, this means that if we move in any direction from the current point, the objective value will either remain constant or degrade.  Such a solution is called a local maximum because it has the largest objective value in a local region.  In contrast, a global maximum is a solution that provides the largest objective value among all feasible solutions.

The Excel worksheet below shows the results of one of several local maxima found for this problem.

 

For this example, we tried five different starting points for the variables P, Q and R. The initial values of all raw material amounts were then chosen so that the raw material constraints were satisfied. The results are shown in Table 4 in the rows labeled Final. In the second run, for example, the initial values were P = 50, Q = 50, R = 50; the algorithm converged to P = 26.7, Q = 40, R = 60 giving Z = 3510. The first run, whose final solution is illustrate above, was obtained by starting the Solver with all production quantities equal to 0. In the third run, the algorithm made no progress.  It terminated at the same point at which it started implying that P = 100, Q = 40, R = 0 is a local optimum.

Table 4. Multiple Local Maxima for the Convex Objective Function
1
2
3
4
5
Initial P
0
50
100
90
50
Initial Q
0
50
40
0
20
Initial R
0
50
0
50
60
Final P
0
26.7
100
90
81.8
Final Q
40
40
40
0
16.4
Final R
60
60
0
60
60
Final A
1000
1533
2400
2400
2400
Final B
2080
2400
2320
2040
2400
Final C
1200
1600
1740
2310
2285
Final D
600
867
1600
900
1063
Final Z
3350
3510
3650
3772
3787

The results in Table 4 indicate the difficulty encountered when maximizing a convex function (or minimizing a concave function) regardless of the feasible region. To a large extent, the path taken by a solution algorithm and the point to which it converges depends on the initial point chosen. All the solutions identified in the table are local optima, but since we don't know if all local optima have been identified, we may not have found the global optimum. Unfortunately, this predicament is all too common when trying to optimize nonlinear functions, and becomes even more disconcerting when there are nonlinearities in the constraints. As the number of nonlinear terms in a problem increases, the amount of work required to find solutions typically goes up at an exponential rate.

The extension of the original linear model to include nonlinear relationships adds more realism to the analysis, but one factor is still missing.  We have not included any requirement for integrality of production and sales.  In fact, integer nonlinear programming problems are more difficult to solve than their linear and nonlinear counterparts.  Most codes for such problems use ad hoc procedures that combine branch and bound with standard NLP solvers.

 

  
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by Paul A. Jensen
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